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  • Find the product (ii) (2/3 xy) * (-9/10 x^2 y^2)

Q : 3        Find the product.

                (ii) (\frac{2}{3}xy)\times (\frac{-9}{10}x^2y^2)

Answers (2)

best_answer

We have,

                         (\frac{2}{3}xy)\times (\frac{-9}{10}x^2y^2) = \frac{-3}{5}x^3y^3

Posted by

Devendra Khairwa

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2×(-9)/3×10xy × x^2y^2

=-18/30x^3y^3

=-3/5x^3y^3

This is ur answer hope it will help u

Thanku

 

Posted by

I am

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