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  • Find the slope of the tangent to the curve y = x ^3 – 3 x + 2 at the point whose x-coordinate is 3.

4) Find the slope of the tangent to the curvey = x ^3 - 3x +2 at the point whose x-coordinate is 3.

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Given curve is,
y = x ^3 - 3x +2
The slope of the tangent at x = 3 is given by
\left ( \frac{dy}{dx} \right )_{x=3} = 3x^2 - 3 = 3(3)^2 - 3= 3\times 9 - 3 = 27 - 3 = 24
Hence, the slope of tangent at point x = 3 is 24

Posted by

Gautam harsolia

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