Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the sum of the first 40 positive integers divisible by 6.

Q : 12    Find the sum of the first \small 40 positive integers divisible by  \small 6.

Answers (1)

best_answer

Positive integers divisible by 6 are 
6,12,18,...
This is an AP with 
here, \ a = 6 \ and \ d = 6
Now, we know that 
S_n= \frac{n}{2}\left \{ 2a+(n-1)d \right \}
\Rightarrow S_{40}= \frac{40}{2}\left \{ 2\times 6+(40-1)6 \right \}
\Rightarrow S_{40}= 20\left \{12+234 \right \}
\Rightarrow S_{40}= 20\left \{246 \right \}
\Rightarrow S_{40}= 4920
Therefore,  sum of the first \small 40 positive integers divisible by  \small 6 is 4920

Posted by

Gautam harsolia

View full answer

Similar Questions

Trending Articles/News

anam-khan

Board Exam Date 2025 Live: Bihar Class 10, 12 model papers out, time table soon; updates on CBSE, UP

Latest Question