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Q : 1    Find the sum of the following APs:

            (iii)   \small 0.6,1.7,2.8,..., to \small 100  terms.

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Given AP is 
 \small 0.6,1.7,2.8,..., to \small 100  terms..
Here, a = 0.6 \ and \ n = 100
And
d = a_2-a_1=1.7-0.6=1.1
Now, we know that 
S = \frac{n}{2}\left \{ 2a+(n-1)d \right \}
\Rightarrow S = \frac{100}{2}\left \{ 2\times (0.6) +(100-1)(1.1)\right \}
\Rightarrow S = 50\left \{ 1.2 +108.9\right \}
\Rightarrow S = 50\left \{ 110.1\right \}
\Rightarrow S =5505
Therefore, the sum of AP \small 0.6,1.7,2.8,..., to \small 100  terms. is 5505

Posted by

Gautam harsolia

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