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Find the term independent of x in the expansion of \left ( 3x-\frac{2}{x^{2}} \right )^{15}

Answers (1)

Given: (3x – 2/x2)15

Thus, T_{r+1} = ^{15}C_r3^{15-r}x^{15-3r}(-2)^r

Now, for independent term x,

15 – 3r = 0

Thus, r = 5

Thus, the term x is

T5+1 = 15C5315-5(-2)5

= -15 x 14 x 13 x 12 x 11 x 10!/5x4x3x2x1x10! .310.25

= -3003 x 310x 25
 

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