Find the term independent of x in the expansion of
Given: (3x – 2/x2)15
Thus,
Now, for independent term x,
15 – 3r = 0
Thus, r = 5
Thus, the term x is
T5+1 = 15C5315-5(-2)5
= -15 x 14 x 13 x 12 x 11 x 10!/5x4x3x2x1x10! .310.25
= -3003 x 310x 25