Find the third vertex of triangle whose centroid is origin and two vertices are (2, 4, 6) and (0, –2, –5).
Given:
Vertices of triangle,
B(2, 4, 6), C(0,-2,-5)
& centroid of triangle, G is (0,0,0)
Let us assume that the unknown vertex of the triangle is A(x,y,z).
Thus,
(0,0,0) ≡ ((2+0+x)/3, (4-2+y)/3, (6-5+z)/3)
Now, when we compare the coordinates, we get,
2+x/3 = 0, thus, x = -2
2+y/3 = 0, thus, y = -2
& 1+z/3 = 0, thus, z = -1.