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Q3. Find the value of.

(i) $(3^0 + 4^{-1})\times 2^2$

Answers (1)

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The detailed explanation for the above-written question is as follows,

As we know that $a^{0}=1$

So, $3^{0}=1$

now,

$=(1+\frac{1}{4})\times 2^{2}$

$=\frac{5}{4}\times 2^{2}\Rightarrow \frac{5}{2^{2}}\times 2^{2}=5/1$

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manish

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