Q5.Find the values of the letters in each of the following and give reasons for the steps involved. .
Here multiplication of 3 and B gives a number whose unit place digit is B .
Possible value of B = 0 and 5
let B = 5
3 * A + 1 = CA
this is not possible for any value of A.
Hence B = 0
now A * 3 = CA ( a number whose unit place digit is A itself when multiplied by 3) hence
possible value of A = 5 and 0
since AB is a two digit number A can not equal to 0.
hence A = 5
A * 3 + 1 = CA
5 * 3 + 1 = 15
hence C = 1
A = 5, B = 5 and C = 1.