Q6.Find the values of the letters in each of the following and give reasons for the steps involved.
Here , multiplication of B and 5 gives a number whose ones digit is B. this is possible when B = 0 or 5
let B = 5
B * 5 = 5 * 5 = 25
Carry = 2
5*A + 2 = CA , This os possible only when A = 2 or 7
when A = 2 ,
5*2 + 2 = 12 which implies C = 1
when A = 7
5*7 + 2 = 37 which implies C = 3
now B = 0
B*5 = 0*5 = 0
Carry = 0 so
5 * A = CA which is possible when A = 0 or 5 Howerver A cannot equal to 0 since AB is a two digit number
so A = 5
5*5 = 25 which implies C = 2
hence possible values of A B and C are
A = 5, 2, 7 , B = 0, 5, 5 and C = 2, 1, 3