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  • Find the values of the trigonometric functions sin (-11pi/3)

Q (9) Find the values of the trigonometric functions

\sin\left ( -\frac{11\pi}{3} \right )

Answers (1)

We know that sin x repeats after an interval of 2\pi or 360\degree
\sin \left ( -\frac{11\pi}{3} \right ) = \sin \left ( -4\pi +\frac{\pi}{3} \right ) = \sin \frac{\pi}{3} = \frac {\sqrt{3}}{2}

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Safeer PP

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