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13.9     Give the structures of A, B and C in the following reactions: 

                (i) CH_{3}CH_{2}I\xrightarrow[]{NaCN}A\xrightarrow[Partial hydrolysis]{OH^{-}}B\xrightarrow[]{NaOH+Br_{2}}C

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In the first reaction, the iodine is replaced by CN so the structure of (A) is CH_{3}CH_{2}CN(propionitrile). On partial hydrolysis, the CN converted into CONH_{2}, So the structure of B is CH_{3}CH_{2}CONH_{2} (propanamide) and the third reactant is Hoffmann bromide degradation reaction, So just remove the -CO group and it becomes a primary aliphatic amine. Thus, the structure of C is CH_{3}CH_{2}NH_{2} (ethanamine)

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