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Given the ellipse with equation 9x2 + 25y2 = 225, find the eccentricity and foci.

Answers (1)

Given equation of ellipse

9x2+25y2=225

\frac{x^{2}}{25}+\frac{y^{2}}{9}=1

a=5, b=3

b2=a2(1-e2)

9=25(1-e2)

e=\frac{4}{5}

\text { Foci } \equiv(\pm a e, 0) \equiv(\pm 5 \times(4 / 5), 0) \equiv(\pm 4,0)

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