3.20 (b) Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them
to get an equivalent resistance of (i)
We Have, equivalent resistance = 11/3
Let's break this algebraically so that we can represent it in terms of 1, 2 and 3
this expression is expressed in terms of 1, 2 and 3. and hence we can make a circuit which consist only of 1 ohm, 2 ohms and 3 ohms and whose equivalent resistance is 11/3. that is :