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  • Given the resistances of 1 Ω, 2 Ω, and 3 Ω, how will be combined to get an equivalent resistance of (11 / 3) Ω?

Given the resistances of 1 Ω, 2 Ω, and 3 Ω, how will combine them to get an equivalent resistance \frac{11}{3}\Omega ?

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We Have, equivalent resistance = 11/3

Let's break this algebraically so that we can represent it in terms of 1, 2 and 3, then. 

\frac{11}{3}=\frac{9+2}{3}=3+\frac{2}{3}=3+\frac{1*2}{1+2}

This expression is expressed in terms of 1, 2 and 3.  Hence we can make a circuit which consists only of 1 ohm, 2 ohms and 3 ohms and whose equivalent resistance is 11/3. That is :

 

Posted by

Pankaj Sanodiya

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