Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Graphically, solve the following pair of equations: 2x + y = 6 2x – y + 2 = 0 Find the ratio of the areas of the two triangles formed by the lines representing these equations with the x-axis and the lines with the y-axis.

Graphically, solve the following pair of equations:2x + y = 6 and  2x – y + 2 = 0 Find the ratio of the areas of the two triangles formed by the lines representing these equations with the x-axis and the lines with the y-axis.

Answers (1)

Solution:
Here the equations are 2x + y = 6, 2x – y = –2
2x + y = 6

x 0 3
y 6 0

2x – y = –2

x 0 -1
y 2 0

In graph we find that the lines are intersecting at (1, 4) Hence x = 1, y = 4 is the solution of the equations.The two triangles are ABC and DBE
Area of \bigtriangleupABE = \frac{1}{2} × Base × perpendicular

  = \frac{1}{2}\times 4\times 4= 8
Area of \bigtriangleupADC = \frac{1}{2} × Base × perpendicular

  = \frac{1}{2}\times 4\times 1

= 2
\bigtriangleupABE area : \bigtriangleupADC Area
4 : 1

Posted by

infoexpert27

View full answer

Similar Questions

Latest Question