Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • How many non square numbers lie between the following pairs of numbers (i) 100^2 and 101^2  (ii) 90^2 and 91^2  (iii) 1000^2 and 1001^2.

Q.2 How many non square numbers lie between the following pairs of numbers

(i) 100^{2}\; and\; 101^{2}

(ii) 90^{2}\; and\; 91^{2}

(iii) 1000^{2}\; and\; 1001^{2}

Answers (4)

best_answer

In general, we can say that there are 2n nonperfect square numbers between the squares of the numbers n and (n + 1). 

(i) The number of non-square numbers that lie between the square of 100 and 101 will be = 2(100)  = 200.

(ii) The number of non-square numbers that lie between the square of 90 and 91 will be = 2(90) = 180.

(iii) The number of non-square numbers that lie between the square of 1000 and 1001 will be = 2(1000) = 2000.

 

Posted by

Devendra Khairwa

View full answer

100 sq and 101 sq =200 non - square lies

90 sq and 91 sq =180 non - square lies 

1000 sq and 1001 sq = 2000 non - square lies

Posted by

Adheena

View full answer

200

Posted by

Ankit

View full answer

1. (10201-10000)-1

201-1

200

2. 8281-8100)-1

180

3. 1001001-1000000

1001

Posted by

Protyush Nandi

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST Class 6 admit card 2025 out at navodaya.gov.in; exam in 2 phases
anam-khan

NVS LEST 2025 application correction deadline today at navodaya.gov.in; editable fields
anam-khan

NVS 2025 application correction window for Class 9, 11 admissions opens at navodaya.gov.in

Latest Question