Get Answers to all your Questions

header-bg qa

How will you construct a 45° angle?

Answers (1)

best_answer

The steps of constructions:

1. Draw a ray OA.

2. Taking O as center and any radius, draw an arc cutting OA at B.

3. Now, taking B as center and with the same radius as before, draw an arc intersecting the previously drawn arc at point C.

4. With C as the center and the same radius, draw an arc cutting the arc at D.

\

5. With C and D as centers and radius more than \frac{1}{2}CD, draw two arcs intersecting at P.

6. Join OP.

Thus, \angle AOP = 90^{\circ}

Now, we draw the bisector of \angle AOP

7. Let OP intersects the original arc at point Q.

8. Now, taking B and Q as centers, and radius greater than \frac{1}{2}BQ, draw two arcs intersecting at R.

9. Join OR.

Thus, \angle AOR = 45^{\circ}

 

Posted by

Divya Prakash Singh

View full answer