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13.3    How will you convert

                (iii)  Cl-(CH_{2})_{4}-Cl   into hexan-1 ,6-diamine?

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ON reacting the given reactant with ethanolic sodium cyanide, the CN molecules replace both chlorine atom. And after that catalytic hydrogenation, we get our desired product. (reduce the CN to -CH_{2}NH_{2} in both sides)

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manish

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