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  • (i) A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

17.(i) A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?

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Total number of bulbs =  20

Hence, total possible outcomes = 20

Number of defective bulbs = 4

Hence,number of favourable outcomes = 4

\therefore P(getting\ a\ defective\ bulb)= \frac{favourable\ outcomes}{total\ outcomes} = \frac{4}{20}

= \frac{1}{5}

Posted by

HARSH KANKARIA

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