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2.28 (i) An atomic orbital has n = 3. What are the possible values of l and m_l?

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For a given value of the principal quantum number $(n)$ , the azimuthal quantum number $(l)$ can have values from $0$ to $(n-1)$ .

Therefore, for given atomic orbital $n =3$ ,

The value of $l$ can take values from $0$ to $(3-1) =2$ , i.e., $l = 0,1,2$ .

And for a given value of $l$ , the Magnetic quantum number $m_{l}$ can have $(2l+1)$ values.

When value of $l =0$ then, $m=0$ ,

or $l=1$ then, $m= -1,0,+1$

or $l=2$ then, $m= -2,-1,0,+1,+2$

or $l=3$ then, $m= -3,-2,-1,0,+1,+2,+3$

Posted by

Divya Prakash Singh

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