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Q1. If 21y5 is a multiple of 9, where y is a digit, what is the value of y?

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If a number is a multiple of 9 , then the sum of its digit will be divisible by 9.

Sum of digits of 21y5= 2 + 1 + y + 5 = 8 + y

8 + y is a multiple of 9 when y = 1 (since y can only be single digit )

hence y = 1 is correct answer.

Posted by

Pankaj Sanodiya

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