Let C = (AB’ - BA’)
C’ = (AB’ - BA’)’
C’ = (AB’)’ - (BA’)’
C’ = (B’)’A’ - (A’)’B’
C’ = BA’ - AB’
C’ = -C
∴ C is a skew-symmetric matrix.
Clearly Option (A) matches with our deduction. Hence we can say that,
∴ Option (A) is the correct.
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