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  • If absolute value of x less than equal to 1, then 2 tan inverse x plus sin inverse 2x divided 1 plus x square is equal to A. 4 tan inverse x B. 0 C. pi divided 2 D pi

If |x| ≤ 1, then 2\tan ^{2}x+\sin^{-1}\frac{2x}{1+x^{2}}  is equal to
A. 4 tan–1 x
B. 0
C. \frac{\pi}{2}
D. π

Answers (1)

Answer(A) 

We need to find, 2 \tan^{-1}x+\sin^{-1}\frac{2x}{1+x^{2}}

We know that

2 \tan^{-1}p=\sin^{-1}\frac{2x}{1+x^{2}}

So,

2 \tan^{1}x+\sin^{-1}\frac{2x}{1+x^{2}}=2 \tan^{1}x+2\tan^{-1}x

=4 \tan^{1}x

 

Posted by

infoexpert24

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