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Q. 10.     If bromine atom is available in the form of, say, two isotopes  _{35}^{79}\textrm{Br}(49.7^{o}/_{o}) and  _{35}^{81}\textrm{Br}(50.3^{o}/_{o}), calculate the average atomic mass of bromine atom.

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Given,  two isotopes  _{35}^{79}\textrm{Br}(49.7^{o}/_{o}) and  _{35}^{81}\textrm{Br}(50.3^{o}/_{o}).

Average atomic mass:

=79\times\frac{49.7}{100}+81\times\frac{50.3}{100}

=\frac{3926.3}{100}+\frac{4074.3}{100}

=\frac{8000.6}{100}

=80.006u.

Posted by

Pankaj Sanodiya

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