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Q 10. If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lies on the third side.

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Given: circles are drawn taking two sides of a triangle as diameters.

Construction: Join AD.

Proof: AB is the diameter of the circle and ADB is formed in a semi-circle.
ADB=90-------1 (angle in a semi-circle)
Similarly,
AC is the diameter of the circle and ADC is formed in a semi-circle.
ADC=90------2(angle in a semi-circle)
From 1 and 2, we have
ADB+ADC=90+90=180

ADB and ADC are forming a linear pair.

Hence, point D lies on this side.

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