If M and N are any two events, the probability that at least one of them occurs is
A. P (M) + P (N) – 2 P (M ∩ N)
B. P (M) + P (N) – P (M ∩ N)
C. P (M) + P (N) + P (M ∩ N)
D. P (M) + P (N) + 2P (M ∩ N)
M and N are two events ……. (given)
Now, P (A U B) = P (A) + P (B) – P (A ∩ B) ……. (by general addition rule)
Thus, P (M U N) = P (M) + P (N) – P (M ∩ N)
Thus, option B is the correct answer.