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  • If one end of a diameter of the circle x square plus y square minus 4x minus 6y plus 11 equal to 0 is (3, 4), then find the coordinate of the other end of the diameter

If one end of a diameter of the circle x2 + y2 – 4x – 6y + 11 = 0 is (3, 4), then find the coordinate of the other end of the diameter.

Answers (1)

Given equation of the circle is

x2+y2-4x-6y+11=0

2g=-4 and 2f=-6

So centre of circle is C(-g,-f) = C(2,3)  

A (3,4) is one end of diameter . Let the other end of the diameter be B (x1, y1)

2=\frac{3+x_{1}}{2} and 3=\frac{4+y_{1}}{2}

x1=1 and y1=2

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infoexpert22

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