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If one end of a diameter of the circle x2 + y2 – 4x – 6y + 11 = 0 is (3, 4), then find the coordinate of the other end of the diameter.
Answers (1)
Given equation of the circle is
x2+y2-4x-6y+11=0
2g=-4 and 2f=-6
So centre of circle is C(-g,-f) = C(2,3)
A (3,4) is one end of diameter . Let the other end of the diameter be B (x1, y1)
and
x1=1 and y1=2
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