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Q. 3.     If  P(A)=0.8,P(B)=0.5   and  P(B\mid A)=0.4,  find

            (iii)  P(A\cup B)

Answers (1)

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It is given that  P(A)=0.8,P(B)=0.5   

P(A\cap B)=0.32

P(A\cup B)=P(A)+P(B)-P(A\cap B)

P(A\cup B)=0.8+0.5-0.32 

P(A\cup B)=1.3-0.32

P(A\cup B)=0.98

Posted by

seema garhwal

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