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  • If sin A = 3/4, calculate cos A and tan A.

3.     If \sin A=\frac{3}{4}, calculate \cos A and \tan A.

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Suppose \DeltaABC is a right-angled triangle in which \angle B = 90^0 and we have \sin A=\frac{3}{4},
So, 

Let the length of AB be 4 unit and the length of BC = 3 unit
So, by using Pythagoras theorem,
AB = \sqrt{16-9} = \sqrt{7} units
Therefore, 
\cos A = \frac{AB}{AC} = \frac{\sqrt{7}}{4}  and \tan A = \frac{BC}{AB} = \frac{3}{\sqrt{7}}

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