Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • If tan A plus B is equal to sqrt 3 and tan A minus B is equal to 1 sqrt 3 0 degree greater than A plus B leq 90 degree A is lesser than B find A and B

3.     If  \tan (A+B)=\sqrt{3} and \tan (A-B)= \frac{1}{\sqrt{3}};  0^{o}<A+B\leq 90^{o};A> B, find A \: and \: B.

Answers (1)

best_answer

Given that,
\tan (A+B) = \sqrt{3} =\tan 60^0
So, A + B = 60^o..........(i)
\tan (A-B) = 1/\sqrt{3} =\tan 30^0
therefore, A - B = 30^o.......(ii)
By solving the equation (i) and (ii) we get;

A = 45^o and B = 15^o
 

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE 10th supplementary result 2025 declared; 48.68% students qualify
anam-khan

CBSE Class 10 Compartment Result 2025 (OUT) LIVE: CBSE 10th supply results declared at cbse.gov.in

Latest Question