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  • If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

2.35    If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

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Given the diameter of a carbon atom which is 0.15\ nm = 0.15\times10^{-9}m = 1.5\times10^{-10} m

Then the number of carbon atoms which can be placed side by side in a straight line across the length of the scale of length 20\ cm long will be:

=\frac{2\times10^{-1}m}{1.5\times10^{-10}m} = 1.33\times10^{9}

 

Posted by

Divya Prakash Singh

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