Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • If the speed of light is 3.0 × 10 8 m s^ –1 , calculate the distance covered by light in 2.00 ns.

1.22    If the speed of light is 3.0 \times 10^8 m s^{-1} , calculate the distance covered by light in 2.00 ns.

Answers (1)

best_answer

Given the speed of light to be 3.0 \times 10^8 m s^{-1}, so the distance covered by light in 2.00 ns. will be:

Distance = Speed\times Time

Distance = (3.0\times10^{8}ms^{-1})\times(2.00\times10^{-9}sec) = 6.00\times10^{-1}m = 0.600m

Therefore, the light will travel 0.600 metres in 2 nano seconds.

Posted by

Divya Prakash Singh

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 history paper 2025 moderately difficult, tested students’ understanding
anam-khan

CBSE Class 12 Computer Science Exam Analysis 2025: Paper 'moderate', but 'tougher' than last three years
anam-khan

CBSE Class 12 Accountancy Exam Analysis 2025: Paper ‘moderate', includes application-based questions

Latest Question