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8.  If the sum of n terms of an A.P. is ( pn + qn ^ 2 ) , where p and q are constants,  find the common difference

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If the sum of n terms of an A.P. is ( pn + qn ^ 2 ),

S_n =\frac{n}{2}[2a+(n-1)d]

\Rightarrow \, \, \frac{n}{2}[2a+(n-1)d]=pn+qn^2

\Rightarrow \, \, \frac{n}{2}[2a+nd-d]=pn+qn^2

\Rightarrow \, \, an+\frac{n^2}{2}d-\frac{nd}{2}=pn+qn^2

Comparing coefficients of n^2 on both side , we get

          \frac{d}{2}=q

     \Rightarrow \, \, d=2q

The common difference of AP is 2q.

Posted by

seema garhwal

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