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  • If the sum of three numbers in A.P., is 24 and their product is 440, find the numbers.

2.  If the sum of three numbers in A.P., is 24 and their product is 440, find the numbers.

Answers (1)

best_answer

Let three numbers of AP are a-d, a, a+d.

According to given information ,

a-d+a+a+d=24

3a=24

 \Rightarrow a=8

(a-d)a(a+d)=440

\Rightarrow (8-d)8(8+d)=440

\Rightarrow (8-d)(8+d)=55

\Rightarrow (8^2-d^2)=55

\Rightarrow (64-d^2)=55

\Rightarrow d^2=64-55=9

\Rightarrow d=\pm 3

When d=3, AP= 5,8,11   also if d=-3   ,AP =11,8,5.

Thus, three numbers are 5,8,11.

Posted by

seema garhwal

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