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Q 3. If two equal chords of a circle intersect within the circle, prove that the line joining the point of intersection to the centre makes equal angles with the chords.
 

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Given: two equal chords of a circle intersect within the circle.

To prove: the line joining the point of intersection to the centre makes equal angles with the chords.
i.e. $\angle \mathrm{OEM}=\angle \mathrm{OEN}$

Proof : 

Construction: Join OE and draw $O M \perp A B$ and $O N \perp C D$.
In $\triangle \mathrm{OME}$ and $\triangle \mathrm{ONE}$,
$\mathrm{AE}=\mathrm{AE} \quad$ (Common)
$\mathrm{OM}=\mathrm{ON} \quad$ (Equal chords of a circle are equidistant from the centre)
$\angle \mathrm{OME}=\angle \mathrm{ONE} \quad$ (Both are right-angled)
Thus, $\triangle \mathrm{OME} \cong \triangle \mathrm{ONE}$ (By RHS rule)
$\angle \mathrm{OEM}=\angle \mathrm{OEN}(\mathrm{CPCT})$

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