Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • If z is a complex number, then A. |z2| > |z|2 B. |z2| = |z|2 C. |z2| < |z|2 D. |z2| ≥ |z|2

If z is a complex number, then
A.|z^2| > |z|^2
B. |z^2| \: \: equals\: \: |z|^2
C.|z^2| < |z|^2
D. |z^2| \geq |z|^2

Answers (1)

. The answer is the option (b).  

Let \: \: z=x+iy \: \: \: \: ,|z|^2=x^2+y^2

Now,z^2=x^2+y^2 i^2+2xyi

z^2=x^2-y^2+2xyi

|z|^2=\sqrt{(x^2-y^2 )^2+(2xy)^2 }

=\sqrt{x^4+y^4+2x^2 y^2} =\sqrt{(x^2+y^2 )^2}

|z|^2=x^2+y^2=|z|^2

Hence, b is correct

 

Posted by

infoexpert21

View full answer

Similar Questions

Latest Question