Get Answers to all your Questions

header-bg qa

2.18 In a hydrogen atom, the electron and proton are bound at a distance of about 0.53 \dot{A}

(a) Estimate the potential energy of the system in eV, taking the zero of the potential energy at an infinite separation of the electron from proton 

Answers (1)

best_answer

As we know,

the distance between electron-proton of the hydrogen atom 

d=0.53*10^{-10}m 

The potential energy of the system = potential energy at infinity - potential energy at distance d

PE=0-\frac{ke*e}{d}=-\frac{9*10^9(1.6*10^{-19})^2}{0.53*10^{10}}=-43.7*10^{-19}J

As we know,

1ev=1.6*10^{-19}J

PE=\frac{-43.7*10^{-19}}{1.6*10^{-19}}=-27.2eV

Hence potential energy of the system is -27.2eV.

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads