Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • In a non-leap year, the probability of having 53 Tuesdays or 53 Wednesdays is A 1 divided 7 B 2 divided 7 C 3 divided 7 D none of these

In a non-leap year, the probability of having 53 Tuesdays or 53 Wednesdays is
A. 1/7
B. 2/7
C. 3/7
D. none of these

Answers (1)

B

(i) A non-leap year contains 365 days. So, by dividing it by 7, we get 52 weeks and 1 more day.
So, since 52 weeks are there, it means 52 Tuesdays will also be there, necessarily with probability I and 1 more day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, or Saturday.
So, to get 53 Tuesdays, we have to select one more Tuesday from these 7 possibilities with probability 1/7.

Therefore, probability of having 53 Tuesdays or 53 Wednesdays in a non-leap year =\frac{1}{7}+ \frac{1}{7}=\frac{2}{7}

 

Posted by

Satyajeet Kumar

View full answer

Similar Questions

Latest Question