Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

10(a) In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of $20 \times 10 ^{10 }Hz$ and amplitude $48 Vm ^{-1}$

What is the wavelength of the wave?

Answers (1)

best_answer

Frequency( $\nu$ ) =20 $\times$ 10¹⁰ Hz

E₀ = 48 Vm^-1

$Wavelength(\lambda) =\frac{Speed\ of\ light(c)}{Frequency (\nu )}$

= $\frac{3\times 10^{8}}{20\times 10^{10}}$

$=1.5 mm$

Posted by

Sayak

View full answer

Crack CUET with india's "Best Teachers"

HD Video Lectures
Unlimited Mock Tests
Faculty Support

cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Result 2025 Live: UK Board 10th, 12th results tomorrow; AP SSC, TS Inter, UP, CBSE updates

anam-khan

When will CBSE Class 12 results 2025 be declared? Last two years' trends

anam-khan

CBSE Class 10, 12 board exams 2025 from April 7 to 11 for sports students

Latest Question