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Get Answers to all your Questions
Q 1. In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water
Answers (3)
Given, the reaction
sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water
5.3g 6g 8.2g 2.2g 0.9g
Now,
Total Mass on the Left Hand Side = 5.3g + 6g = 11.3g
Total Mass on the Right Hand Side = 8.2g + 2.2g + 0.9g = 11.3g
As Mass on the LHS is equal to RHS, the observation is in agreement with the law of conservation of mass.
Given->
Reactants=>
Sodium caronate=5.3g
Ethanoic acid =6g
Products=>
Carbon dioxide = 2.2g
Water = 0.9g
Sodium Ethanoate = 8.2g
Reactants ---------> Products
Sodium carbonate+Ethanoic acid -----------> Carbon dioxide + Water + Sodium Ethanoate
Reactants => 5.3g+6g = 11.3g
Products=> 2.2g+0.9g+8.2g=11.3g
As mass of the Reactants is equals to Products , The observation is in agreement with the law of conservation of mass.
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