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  • In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these

Q 1.     In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.

sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water

Answers (3)

best_answer

Given, the reaction 

 sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water

        5.3g                       6g                     8.2g                     2.2g               0.9g

Now,

Total Mass on the Left Hand Side = 5.3g + 6g = 11.3g

Total Mass on the Right Hand Side = 8.2g + 2.2g + 0.9g = 11.3g

As Mass on the LHS is equal to RHS, the observation is in agreement with the law of conservation of mass. 

Posted by

Pankaj Sanodiya

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Posted by

Matt

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Given->

Reactants=> 

Sodium caronate=5.3g

Ethanoic acid =6g

Products=>

Carbon dioxide = 2.2g

Water = 0.9g 

Sodium Ethanoate = 8.2g

Reactants  ---------> Products

Sodium carbonate+Ethanoic acid -----------> Carbon dioxide + Water + Sodium Ethanoate 

Reactants => 5.3g+6g = 11.3g

Products=> 2.2g+0.9g+8.2g=11.3g

As mass of the Reactants is equals to Products , The observation is in agreement with the law of conservation of mass.

Posted by

Yash bhalse

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