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Q.7 In a right triangle $ABC,\angle B=90^{\circ}$

(b) If $AC=13\; cm,$ $BC=5\; cm,$ find $AB$

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Using Pythagoras theorem,

$AC^2 = AB^2 + BC^2$

or $13^2 = AB^2 + 5^2$

or $169 = AB^2 + 25$

or $AB^2 =169 - 25= 144$

Prime factorisation of 144 gives :- $2\times2\times2\times2\times3\times3$

Hence, AB = 12 cm

Posted by

Devendra Khairwa

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