Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • In accordance with the Bohr’s model, find the quantum number that characterises the earth’s revolution around the sun in an orbit of radius 1.5 × 10^11 m with orbital speed 3 × 10^4 m/s. (Mass of earth = 6.0 × 10^24 kg.)

Q 12.10  In accordance with the Bohr’s model, find the quantum number that characterises the earth’s revolution around the sun in an orbit of radius   1.5 \times 10^{11}m m with orbital speed 3 \times 10^{4}m/s  (Mass of earth = 6.0 \times 10^{24}kg.)

Answers (1)

best_answer

As per the Bohr's model, the angular of the Earth will be quantized and will be a multiple of \frac{h}{2 \pi}

\\mvr=\frac{nh}{2 \pi}\\ n=\frac{2 \pi mvr}{h}\\ n=\frac{2\pi\times 6\times 10^{24}\times 3\times 10^{4}\times 1.5\times 10^{11}}{6.62\times 10^{-34}}

n = 2.56\times1074

Therefore the quantum number that characterises the earth’s revolution around the sun in an orbit of radius   1.5 \times 10^{11}m m with an orbital speed 3 \times 10^{4}m/s

is 2.56\times1074

Posted by

Sayak

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question