Get Answers to all your Questions

header-bg qa

Q. 4.  In answering a question on a multiple choice test, a student either knows the answer or guesses. Let \frac{3}{4} be the probability that he knows the answer and\frac{1}{4} be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability \frac{1}{4} . What is the probability that the student knows the answer given that he answered it correctly?

Answers (1)

best_answer

A : Student knows answer.

B : Student guess the answer

C : Answer is correct 

P(A)=\frac{3}{4}         P(B)=\frac{1}{4}

P(C|A)=1

P(C|B)=\frac{1}{4}

By Bayes theorem :

P(A|C)=\frac{P(A).P(C|A)}{P(A).P(C|A)+P(B).P(C|B)}

                 P(A|C)=\frac{\frac{3}{4}\times 1}{\frac{3}{4}\times 1+\frac{1}{4}\times \frac{1}{4}}

                  =\frac{\frac{3}{4}}{\frac{3}{4}+\frac{1}{16}}     =\frac{\frac{3}{4}}{\frac{13}{16}}

                 P(A|C)=\frac{12}{13}

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads