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Q 10.25 In deriving Bernoulli’s equation, we equated the work done on the fluid in the tube to its change in the potential and kinetic energy.

(a) What is the largest average velocity of blood flow in an artery of diameter 2 × 10–3 m if the flow must remain laminar?

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The diameter of the artery is d=2\times 10^{-3}m

The viscosity of blood is \eta =2.08\times 10^{-3}\ Pa\ s

The density of blood is \rho =1.06\times 10^{3}\ kg\ m^{-3}

The average velocity is given by v_{avg}=\frac{N_{Re}\eta }{\rho d}

Taking the Maximum value of Reynold's Number ( NRe = 2000) at which Laminar Flow takes place we have

\\v_{avg,max}=\frac{2000\times 2.08\times 10^{-3}}{1.06\times 10^{3}\times 2\times 10^{-3}}\\ v_{avg,max}=1.97ms^{-1}

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