Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin. (d) 5 y+8= 0

1     In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

     (d)     5y + 8 = 0

Answers (1)

best_answer

Given the equation of plane is 5y+8=0  or we can write 0x-5y+0z=8

So, the direction ratios of normal from the above equation are, 0,\ -5,\ and\ 0.

Therefore \sqrt{0^2+(-5)^2+0^2} =5

Then dividing both sides of the plane equation by 5, we get

-y = \frac{8}{5}

So, this is the form of  lx+my+nz = d the plane, where l,\ m,\ n are the direction cosines of normal to the plane and d is the distance of the perpendicular drawn from the origin.

\therefore The direction cosines of the given line are 0,\ -1,\ and\ 0 and the distance of the plane from the origin is \frac{8}{5} units.

Posted by

Divya Prakash Singh

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam 2025: Class 9, 11 registration begins today; fee details, guidelines
anam-khan

Submit list of candidates for CBSE board exams 2025 correctly, on time: Schools reminded
anam-khan

CBSE sample paper 2024-25, marking scheme out for skill education subjects

Latest Question