Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • In Fig, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

15. In Fig, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

 

Answers (1)

best_answer

Consider \Delta ABC,

BC^2\ =\ AC^2\ +\ AB^2

=\ 14^2\ +\ 14^2

BC\ =\ 14\sqrt{2}\ cm                                          

The area of the triangle is :

=\ \frac{1}{2}\times 14\times 14

=\ 98\ cm^2         

Now, the area of the sector is :  

=\ \frac{90^{\circ}}{360^{\circ}}\times \pi \times 14^2

=\ 154\ cm^2

The area of the semicircle is: - 

=\ \frac{1}{2} \pi r^2

=\ \frac{1}{2} \pi \times (7\sqrt{2})^2

=\ 154\ cm^2

Hence the area of the shaded region =\ 154\ -\ (154\ -\ 98)\ =\ 98\ cm^2 

Posted by

Devendra Khairwa

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 10 Hindi Exam Analysis 2025: Paper ‘well-organised, moderately difficult'; MCQ section easy
anam-khan

No change in CBSE Class 10 subjects for 2026, board will offer 45 languages: Chairman clarifies
anam-khan

Minister objects to Punjabi's absence from list in CBSE draft; board says language list 'indicative'

Latest Question