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  • In Fig. 6.32, if AB || CD, ∠ APQ = 50° and ∠ PRD = 127°, find x and y.

5.  In Fig. 6.32, if AB || CD, \angle APQ = 50° and \angle PRD = 127°, find x and y.

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Given, AB || CD, \angleAPQ = 50^0 and \anglePRD = 127^0
PQ is a transversal. So, 
\angleAPQ = \anglePQR= 50^0 (alternate interior angles)
\therefore x = 50^0

Again, PR is a transversal. So, 
\angley + 50^0 = 127^0 (Alternate interior angles)
\Rightarrow y = 77^0

Posted by

manish painkra

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