Q6 In Fig. 6.37, if ABE ACD, show that ADE ~ ABC.

Name: In Fig. 6.37, if D ABE equivalent Delta ACD, show that D ADE ~ D ABC.
Uploaded: Fri, 2019-06-21 15:53
Description: In Fig. 6.37, if D ABE equivalent Delta ACD, show that D ADE ~ D ABC.

In Fig. 6.37, if D ABE equivalent Delta ACD, show that D ADE ~ D ABC.

#CBSE 10 Class
#Mathematics Textbook for Class X
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Q6 In Fig. 6.37, if $\Delta$ ABE $\equiv$ $\Delta$ ACD, show that $\Delta$ ADE ~ $\Delta$ ABC.

Answers (1)

Given : $\triangle ABE \cong \triangle ACD$

To prove ADE ~ $\Delta$ ABC.

Since $\triangle ABE \cong \triangle ACD$

$AB=AC$ ( By CPCT)

$AD=AE$ (By CPCT)

In $\Delta$ ADE and $\Delta$ ABC,

$\angle A=\angle A$ ( Common)

and

$\frac{AD}{AB}=\frac{AE}{AC}$ ( $AB=AC$ and $AD=AE$ )

Therefore, $\Delta$ ADE ~ $\Delta$ ABC. ( By SAS criteria)

Posted by

seema garhwal

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Q6 In Fig. 6.37, if ABE ACD, show that ADE ~ ABC.

Answers (1)

Posted by

seema garhwal

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Q6 In Fig. 6.37, if $\Delta$ ABE $\equiv$ $\Delta$ ACD, show that $\Delta$ ADE ~ $\Delta$ ABC.