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  • In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle AEP similar to triangle ADB

Q7  In Fig. 6.38, altitudes AD and CE of \Delta ABC intersect each other at the point P. Show that  \Delta AEP \sim \Delta ADB     

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To prove : \Delta AEP \sim \Delta ADB

In \Delta AEP \, \, \, and\, \, \Delta ADB,

 \angle AEP=\angle ADB     ( Both angles are right angle)

  \angle A=\angle A            (Common )

\Delta AEP \sim \Delta ADB    ( By AA criterion)

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seema garhwal

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