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  • In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle AEP is similar to triangle CDP

Q7 (1)   In Fig. 6.38, altitudes AD and CE of \Delta ABC intersect each other at the point P. Show that:

             \Delta AEP \sim \Delta CDP

          

Answers (1)

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To prove : \Delta AEP \sim \Delta CDP

In \Delta AEP \, \, and\, \, \Delta CDP,

        \angle AEP=\angle CDP     ( Both angles are right angle)

     \angle APE=\angle CPD        (Vertically opposite angles )

\Delta AEP \sim \Delta CDP    ( By AA criterion)

 

Posted by

seema garhwal

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